满分5 >
高中数学试题 >
已知实数a,b,c,d成等比数列,且对函数y=ln(x+2)-x,当x=b时取到...
已知实数a,b,c,d成等比数列,且对函数y=ln(x+2)-x,当x=b时取到极大值c,则ad等于( )
A.-1
B.0
C.1
D.2
考点分析:
相关试题推荐
设实数a、b、c满足c<b<a,且ac<0,那么下列不等式中不一定成立 的是( )
A.ab>ac
B.c(b-a)>0
C.cb<ab
D.ac(a-c)<0
查看答案
设
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223317726400422/SYS201311012233177264004001_ST/0.png)
,
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223317726400422/SYS201311012233177264004001_ST/1.png)
为坐标原点,动点p(x,y)满足
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223317726400422/SYS201311012233177264004001_ST/2.png)
,,则z=y-x的最大值是( )
A.-1
B.1
C.-2
D.
查看答案
若集合A={x||x|≤1,x∈R},B={y|y=x
2,x∈R},则A∩B=( )
A.{x|-1≤x≤1}
B.{x|x≥0}
C.{x|0≤x≤1}
D.∅
查看答案
已知点
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223317726255431/SYS201311012233177262554019_ST/0.png)
,点B为(x,ln(x+1)),向量
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223317726255431/SYS201311012233177262554019_ST/1.png)
,令
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223317726255431/SYS201311012233177262554019_ST/2.png)
,
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223317726255431/SYS201311012233177262554019_ST/3.png)
.
(Ⅰ)求函数y=f(x)的解析式;
(Ⅱ)若
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223317726255431/SYS201311012233177262554019_ST/4.png)
在x∈(0,+∞)时恒成立,求整数k的最大值.
查看答案
已知函数f(x)=
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223317726255431/SYS201311012233177262554018_ST/0.png)
x
3-x,数列{a
n}满足条件:a
1≥1,a
n+1≥f′(a
n+1),
(1)证明:a
n≥2
n-1(n∈N
*)
(2)试比较
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223317726255431/SYS201311012233177262554018_ST/1.png)
+…+
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223317726255431/SYS201311012233177262554018_ST/2.png)
与1的大小,并说明理由.
查看答案