满分5 >
高中数学试题 >
已知直线l是抛物线y=x2的一条切线,且l与直线2x-y+4=0平行,则直线l的...
已知直线l是抛物线y=x2的一条切线,且l与直线2x-y+4=0平行,则直线l的方程是( )
A.2x-y+3=0
B.2x-y-3=0
C.2x-y+1=0
D.2x-y-1=0
考点分析:
相关试题推荐
设集合M={x|x
2-2x-3<0},
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529080437318/SYS201311031005290804373002_ST/0.png)
,则M∩N等于( )
A.(-1,1)
B.(1,3)
C.(0,1)
D.(-1,0)
查看答案
已知tanθ=2,则
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529080437318/SYS201311031005290804373001_ST/0.png)
=( )
A.-2
B.2
C.0
D.
查看答案
已知复数z满足
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529080437318/SYS201311031005290804373000_ST/0.png)
,其中i为虚数单位,则复数z的虚部是( )
A.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529080437318/SYS201311031005290804373000_ST/1.png)
B.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529080437318/SYS201311031005290804373000_ST/2.png)
C.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529080437318/SYS201311031005290804373000_ST/3.png)
D.
查看答案
已知:在△ABC中,a,b,c分别是∠A,∠B,∠C的对边.
求证:
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103100529080283946/SYS201311031005290802839022_ST/0.png)
.
查看答案
已知函数f(x)=ax
2-(a+2)x+lnx.
(Ⅰ)当a=1时,求曲线y=f(x)在点(1,f(1))处的切线方程;
(Ⅱ)当a>0时,函数f(x)在区间[1,e]上的最小值为-2,求a的取值范围;
(Ⅲ)若对任意x
1,x
2∈(0,+∞),x
1<x
2,且f(x
1)+2x
1<f(x
2)+2x
2恒成立,求a的取值范围.
查看答案