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位于数轴原点的一只电子兔沿着数轴按下列规则移动:电子兔每次移动一个单位,移动的方...
位于数轴原点的一只电子兔沿着数轴按下列规则移动:电子兔每次移动一个单位,移动的方向向左或向右,并且向左移动的概率为
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101222810864541163/SYS201311012228108645411006_ST/0.png)
,向右移动的概率为
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101222810864541163/SYS201311012228108645411006_ST/1.png)
,则电子兔移动五次后位于点(-1,0)的概率是( )
A.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101222810864541163/SYS201311012228108645411006_ST/2.png)
B.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101222810864541163/SYS201311012228108645411006_ST/3.png)
C.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101222810864541163/SYS201311012228108645411006_ST/4.png)
D.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101222810864541163/SYS201311012228108645411006_ST/5.png)
考点分析:
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=( )
A.π
B.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101222810864541163/SYS201311012228108645411005_ST/1.png)
C.π+1
D.π-1
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![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101222810864541163/SYS201311012228108645411004_ST/images0.png)
阅读如图的程序框图.若输入m=4,n=6,则输出的a,i分别等于( )
A.12,2
B.12,3
C.24,2
D.24,3
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已知函数
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101222810864541163/SYS201311012228108645411003_ST/0.png)
(ω>0)和g(x)=3cos(2x+φ)的图象的对称中心完全相同,若
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101222810864541163/SYS201311012228108645411003_ST/1.png)
,则f(x)的取值范围是( )
A.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101222810864541163/SYS201311012228108645411003_ST/2.png)
B.[-3,3]
C.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101222810864541163/SYS201311012228108645411003_ST/3.png)
D.
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下列有关命题的说法正确的是( )
A.命题“若x
2=1,则x=1”的否命题为:“若x
2=1,则x≠1”
B.“x=-1”是“x
2-5x-6=0”的必要不充分条件
C.命题“∃x∈R,使得x
2+x+1<0”的否定是:“∀x∈R,均有x
2+x+1<0”
D.命题“若x=y,则sinx=siny”的逆否命题为真命题
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若复数
2(i为虚数单位)是纯虚数,则实数a=( )
A.±1
B.-1
C.0
D.1
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