定义在(-1,1)的函数f(x)满足:①对任意x,y∈(-1,1)都有f(x)+f(y)=
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;②当0<x<1时,f(x)>0.回答下列问题.
(1)判断函数f(x)的奇偶性,并说明理由;
(2)判断函数f(x)在(-1,1)上的单调性,并说明理由;
(3)若
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,试求
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的值.
考点分析:
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=
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,试用
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表示
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已知向量
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