设x
1、x
2(x
1≠x
2)是函数f(x)=ax
3+bx
2-a
2x(a>0)的两个极值点.
(I)若x
1=-1,x
2=2,求函数f(x)的解析式;
(II)若
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024183252755597744/SYS201310241832527555977019_ST/0.png)
,求b的最大值;
(III)设函数g(x)=f'(x)-a(x-x
1),x∈(x
1,x
2),当x
2=a时,求证:
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131024183252755597744/SYS201310241832527555977019_ST/1.png)
.
考点分析:
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