满分5 >
高中数学试题 >
方程lgx-2x+11=0的解为x,若不等式x≤x,则x的最大整数是 .
方程lgx-2x+11=0的解为x,若不等式x≤x,则x的最大整数是 .
考点分析:
相关试题推荐
幂函数y=f(x)的图象过
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102024844743675/SYS201311031020248447436011_ST/0.png)
,则该函数的解析式为f(x)=
.
查看答案
定义:若存在常数k,使得对定义域D内的任意两个不同的实数x
1,x
2,均有
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102024844743675/SYS201311031020248447436009_ST/0.png)
成立,则称函数f(x)在定义域D上满足类利普希茨条件.对于函数
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102024844743675/SYS201311031020248447436009_ST/1.png)
满足利普希茨条件,则常数k的最小值应是( )
A.2
B.4
C.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102024844743675/SYS201311031020248447436009_ST/2.png)
D.
查看答案
函数y=log
ax在[2,+∞)上恒有|y|>1,则实数a的取值范围是( )
A.(
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102024844743675/SYS201311031020248447436008_ST/0.png)
,1)∪(1,2)
B.(0,
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102024844743675/SYS201311031020248447436008_ST/1.png)
)∪(1,2)
C.(1,2)
D.(0,
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103102024844743675/SYS201311031020248447436008_ST/2.png)
)∪(2,+∞)
查看答案