某足球俱乐部和其他4支俱乐部进行足球联赛,它要与其他每支球队各赛一场,在4场的任意一场中,此俱乐部每次胜、负、平的概率相等.已知当这四场比赛结束后,该俱乐部胜场多于负场.
(Ⅰ)求该俱乐部胜场多于负场的所有可能的个数和;
(Ⅱ)若胜场次数为X,求出X的分布列并求X的数学期望.
考点分析:
相关试题推荐
如图,在五面体ABCDEF中,FA⊥平面ABCD,AD∥BC∥FE,AB⊥AD,M为EC的中点,AF=AB=BC=FE=
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223309875291692/SYS201311012233098752916017_ST/0.png)
AD,
(1)求异面直线BF与DE所成的角的大小;
(2)证明平面AMD⊥平面CDE;
(3)求二面角A-CD-E的余弦值.
查看答案
在△ABC中,角A,B,C所列边分别为a,b,c,且
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223309875291692/SYS201311012233098752916016_ST/0.png)
.
(Ⅰ)求角A;
(Ⅱ)若
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223309875291692/SYS201311012233098752916016_ST/1.png)
,试判断bc取得最大值时△ABC形状.
查看答案
给出以下四个命题:
①设a是实数,i是虚数单位,若
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223309875291692/SYS201311012233098752916015_ST/0.png)
是实数,则a=1;
②不等|x-1|+|x-2|≤2的解集为
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223309875291692/SYS201311012233098752916015_ST/1.png)
;
③
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223309875291692/SYS201311012233098752916015_ST/2.png)
;
④已知命题p:在△ABC中,如果cos
2A=cos
2B,则A=B;命题
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223309875291692/SYS201311012233098752916015_ST/3.png)
在定义城内是减函数,则“p∧q”为真,“p∧q”为假,“¬p”为真.
其中正确命题的序号是
.(请把正确的序号全部填上)
查看答案
已知向量
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223309875291692/SYS201311012233098752916014_ST/0.png)
=(2,1),
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223309875291692/SYS201311012233098752916014_ST/1.png)
=(1,7),
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223309875291692/SYS201311012233098752916014_ST/2.png)
=(5,1),设X是直线OP上的一点(O为坐标原点),那么
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223309875291692/SYS201311012233098752916014_ST/3.png)
的最小值是
.
查看答案
已知椭圆
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223309875291692/SYS201311012233098752916013_ST/0.png)
+
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131101223309875291692/SYS201311012233098752916013_ST/1.png)
=1的左、右焦点分F
1、F
2,M是椭圆上一点,N是MF
1的中点,若|ON|=1(O为坐标原点),则|MF
1|等于
.
查看答案