满分5 >
高中数学试题 >
已知复数z的实部为1,且|z|=2,则复数z的虚部是( ) A. B. C. D...
已知复数z的实部为1,且|z|=2,则复数z的虚部是( )
A.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124247471714544/SYS201310251242474717145001_ST/0.png)
B.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124247471714544/SYS201310251242474717145001_ST/1.png)
C.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124247471714544/SYS201310251242474717145001_ST/2.png)
D.
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124247471714544/SYS201310251242474717145001_ST/3.png)
考点分析:
相关试题推荐
设集合A={x|-1≤x≤2,x∈N},集合B={2,3},则A∪B=( )
A.{1,2,3}
B.{0,1,2,3}
C.{2}
D.{-1,0,1,2,3}
查看答案
已知函数f(x)=a
x+x
2-xlna(a>1).
(Ⅰ)试讨论函数f(x)的单调性;
(Ⅱ)若函数y=|f(x)-t|-1有三个零点,试求t的值;
(Ⅲ)若存在x
1,x
2∈[-1,1],使得|f(x
1)-f(x
2)|≥e-1,试求a的取值范围.
查看答案
设圆C
1:x
2+y
2-10x-6y+32=0,动圆C
2:x
2+y
2-2ax-2(8-a)y+4a+12=0,
(Ⅰ)求证:圆C
1、圆C
2相交于两个定点;
(Ⅱ)设点P是椭圆
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124235343243730/SYS201310251242353432437019_ST/0.png)
上的点,过点P作圆C
1的一条切线,切点为T
1,过点P作圆C
2的一条切线,切点为T
2,问:是否存在点P,使无穷多个圆C
2,满足PT
1=PT
2?如果存在,求出所有这样的点P;如果不存在,说明理由.
查看答案
已知数列{a
n}满足
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124235343243730/SYS201310251242353432437018_ST/0.png)
.
(Ⅰ)求数列{a
n}的通项公式;
(Ⅱ)设数列{b
n}的前n项和为
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124235343243730/SYS201310251242353432437018_ST/1.png)
,试求数列
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124235343243730/SYS201310251242353432437018_ST/2.png)
的前n项和T
n;
(Ⅲ)记数列
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124235343243730/SYS201310251242353432437018_ST/3.png)
的前n项积为
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124235343243730/SYS201310251242353432437018_ST/4.png)
,试证明:
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131025124235343243730/SYS201310251242353432437018_ST/5.png)
.
查看答案
如图:四棱锥S-ABCD中,底面ABCD是直角梯形,且∠DAB=90°,E为SD的中点,SA⊥平面ABCD,且AB=1,SA=AD=CD=2.延长DA,与CB的延长线交于点M.
(Ⅰ)求四棱锥S-ABCD的体积;
(Ⅱ)求证:AE∥平面SBC;
(Ⅲ)求证:平面SMC⊥平面SCD.
查看答案