满分5 > 初中数学试题 >

解方程:

解方程:6ec8aac122bd4f6e

 

【解析】【解析】 原方程组即为   ············································· (2分)             由方程(1)代人(2)并整理得:             ··············································································· (2分)            解得,······································································· (2分) 代人得
复制答案
考点分析:
相关试题推荐

如图(8),6ec8aac122bd4f6e

6ec8aac122bd4f6e

 

查看答案

先化简,后计算:6ec8aac122bd4f6e,其中6ec8aac122bd4f6e6ec8aac122bd4f6e.

 

查看答案

计算: 6ec8aac122bd4f6e

 

 

查看答案

如图(7)所示,已知6ec8aac122bd4f6e点从点(1,0)出发,以每秒1个单位长的速度沿着6ec8aac122bd4f6e轴的正方向运动,经过6ec8aac122bd4f6e秒后,以6ec8aac122bd4f6e6ec8aac122bd4f6e为顶点作菱形6ec8aac122bd4f6e,使6ec8aac122bd4f6e6ec8aac122bd4f6e点都在第一象限内,且6ec8aac122bd4f6e,又以6ec8aac122bd4f6e(0,4)为圆心,6ec8aac122bd4f6e为半径的圆恰好与6ec8aac122bd4f6e所在直线相切,则6ec8aac122bd4f6e          .

6ec8aac122bd4f6e

 

查看答案

 

6ec8aac122bd4f6e

 

查看答案
试题属性

Copyright @ 2008-2019 满分5 学习网 ManFen5.COM. All Rights Reserved.