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已知:函数y=f(x-1)的图象关于直线x=1对称,当x>0时,f(x)=x2-...
已知:函数y=f(x-1)的图象关于直线x=1对称,当x>0时,f(x)=x2-2x,则当x<0时,f(x)=( )
A.x2-2
B.x2-2
C.-x2+2
D.x2+2
考点分析:
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若
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,则tanα=( )
A.1
B.-1
C.
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D.
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函数
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的定义域为( )
A.
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B.
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C.{x|2kπ≤x<2kπ+
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},k∈Z}∪{x|x=2kπ+π,k∈Z}
D.
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且x≠2kπ+π,k∈Z}
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集合A={-1,0,1},B={y|y=cosx,x∈A},则A∩B=( )
A.{0}
B.{1}
C.{0,1}
D.{-1,0,1}
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在数列{a
n}中,已知a
1=-1,a
n+1=S
n+3n-1(n∈N
*)
①求数列{a
n}的通项公式
②若b
n=3
n+(-1)
n-1•λ•(a
n+3)(λ为非零常数),问是否存在整数λ使得对任意n∈N
*都有b
n+1>b
n?若存在,求出λ的值;若不存在,请说明理由.
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已知数列{a
n}满足a
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103095916581208784/SYS201311030959165812087020_ST/0.png)
,且对任意n∈N
+,都有
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103095916581208784/SYS201311030959165812087020_ST/1.png)
.
(1)求{a
n}的通项公式;
(2)令b
n=a
n•a
n+1,T
n=b
1+b
2+b
3+…+b
n,求证:
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103095916581208784/SYS201311030959165812087020_ST/2.png)
.
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