已知函数f(x)是定义在(-1,1)上的奇函数,当x∈(0,1)时,f(x)=2
x,
(1)求函数f(x)的解析式;
(2)已知f(x)≤2a恒成立,求常数a的取值范围.
考点分析:
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已知函数
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,x∈R.
(1)求函数f(x)的最大值和最小正周期;
(2)设△ABC的内角A,B,C的对边分别a,b,c,且c=3,f(C)=0,若sin(A+C)=2sinA,求a,b的值.
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已知平面向量
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=(1,x),
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=(2x+3,-x)(x∈R).
(1)若
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⊥
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,求x的值;
(2)若
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103095916579827324/SYS201311030959165798273015_ST/4.png)
∥
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,求|
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-
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|.
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①函数
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103095916579827324/SYS201311030959165798273014_ST/0.png)
在[0,π]上是减函数;
②点A(1,1)、B(2,7)在直线3x-y=0两侧;
③数列{a
n}为递减的等差数列,a
1+a
5=0,设数列{a
n}的前n项和为S
n,则当n=4时,S
n取得最大值;
④定义运算
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103095916579827324/SYS201311030959165798273014_ST/1.png)
则函数
![manfen5.com 满分网](http://img.manfen5.com/res/GZSX/web/STSource/20131103095916579827324/SYS201311030959165798273014_ST/2.png)
的图象在点
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处的切线方程是6x-3y-5=0.
其中正确命题的序号是
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则3x-y的最小值是
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