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已知t为常数,函数y=|x2-2x-t|在区间[0,3]上的最大值为2,则t= ...
已知t为常数,函数y=|x2-2x-t|在区间[0,3]上的最大值为2,则t= .
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设向量
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,
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满足|
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|=|
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|=1,
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•
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=
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,(
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-
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)•(
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-
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)=0,则|
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|的最大值为( )
A.
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B.
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C.
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D.1
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(k为常数),若z=x+y的最大值为6,则k的值为( )
A.9
B.-9
C.6
D.-6
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